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Arjun travels from A to B, a distance of 200 Km at the speed of 40 Km/hr. At the same time, Rakesh starts from point C at a speed of 20 Km/hr along a roadwhich is perpendicular to AB. Find the time in which Arjun & Rakesh will be closer to each other? ​

answers: 1
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Answer:

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Let the C.P. of the article be Rs. x.

Then S.P. at a loss of 10%

100

x×90

= Rs.

100

90x

S.P. at a gain of 12

2

1

%=

100

x×112.5

= Rs.

100

112.5x

Given,

100

112.5x

100

90x

=9

100

22.5x

=9

⇒x=

22.5

900

= Rs. 40

371
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