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Answer:

(k – 1)² + kx + 1

One zero is – 3, so it must satisfy the equation and make it zero.

∴ (k- 1) (- 3)² + k(-3) + 1 =0

⇒ 9k – 9 – Ik + 1 = 0

⇒ 6k – 8 = 0

⇒ k = 8/6 = 4/3

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