a carnot engine having efficiency 1/5 has source temperature pf 527°c . what must be change in sink temperature so that efficiency becomes 1/8​

The change in sink temperature is 60 K

Given :

A Carnot engine having efficiency 1/5 has source temperature of 527°C

To find :

the change in sink temperature so that efficiency becomes 1/8

Solution :

The formula for efficiency of Carnot Engine is given by,

where

T₂ denotes the temperature of sink

T₁ denotes the temperature of source

Case - (i) :

efficiency, η = 1/5

T₁ = 527°C = 527 + 273 K = 800 K

The temperature of the sink when efficiency is 1/5 is 640 K

Case - (ii) :

efficiency, η = 1/8

T₁ = 800 K

The temperature of the sink when efficiency becomes 1/8 is 700 K

The change in sink temperature :

= 700 K - 640 K

= 60 K