Find the smallest number which when divided by 30, 40 and 50leaves the remainder 5 in each case.

answer is 125

50 divided by 125 leaves remainder 5

same with every number because lcm of 30 , 40, 50 is 120 hence it is divisible we add the required remainder to it

required remainder is 5 then 120 + 5 = 125 //