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reconcile reconcile Dec 10, 2020

Find the smallest number which when divided by 30, 40 and 50leaves the remainder 5 in each case.

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Answer:

answer is 125

50 divided by 125 leaves remainder 5

same with every number because lcm of 30 , 40, 50 is 120 hence it is divisible we add the required remainder to it

required remainder is 5 then 120 + 5 = 125 //

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Miller Miller
Dec 10, 2020
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