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Find two consecutive positive integers,sum of whose square is 365​

answers: 1
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Answer:

182+183=365

let one of the no be X

therefore the second no will be X+1

sum of these no will be 365 therefore X+(X+1)=365

= 2X+1=365

= 2X=364

= X=364 / 2 = 182

hence the first no is 182 and second no is 182+1=183

VERIFICATION

182+183=365

hope this helps u out

175
Zhan
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