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The length of a rectangle is six times its width. If the area of the rectangle is 150 cm find its perimeter. ​

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Answer:

98 inches

6x^2=294

x^2=49

x=7

2*7+2*42=  14+84=98 inches

length the width be= W

let the length be =6×W=6W

area = length ×width

294=6W × W

294= 6w^2

49=w^2

the square root of 49 is 7

so the width is 7

while the length is 7 ×6=42

perimeter=2(L+W)

p=2(42+7)

p=2(49)

p= 98

w - width

6w - length

486 in² - area of the rectangle

(w)(6w) = 6w² - area of the rectangle

The equation:

6w² = 486     divide both sides by 6

w² = 81 → w = √81

w = 9 in

l = 6w → l = (6)(9) → l = 54 in

The perimeter: P = 2l + 2w

P = 2(54) + 2(9) = 108 + 18 = 126 in

The perimeter is 126in

X=7

Since area of a rectangle is 294

Area of a rectangle=length×breadth

Let's the width be x

Since length is 6 times of width=6x

Area=l×w

294=x×6x

294=6x^2

Divide both sides by 6

x^2=49

Square root both sides

x=7

Therefore x is 7

Do 600 divided by 6 and it will equal 100 so you answer is 100L = 6w
A = 216
A = lw
216 = (6w)(w)
216 = 6w^2
216/6 = w^2
36 = w^2
w = 6
l = 6(6)
l = 36
P = 2l + 2w
P = 2(36) + 2(6)
P = 72 + 12
P=84Rectangle area = a*b
perimeter = 2(a+b)

a - lenght
b - width

a = 6b

a*b=600
6b*b=600



b=10
a = 6*10 = 60
Perimeter = 2(a+b)=2(60+10)=2*70=140 ydSolutions = 504 answerWidth= w
lenght = 6 width = 6w

area= 284 yd²
       = (width)(length)
       = (w)(6w)
       = 6w²

6w²= 284
w²= 284/6
    = 47.333333
w=√47.2
  = 6.88 inches

perimenter = 2width+ 2 lenght
                  = 2(w) + 2(6w)
                  = 2w+12w
                  = 14w
                  = 14(6.88)
                  = 96.28 inches
450
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