Amanda Williams
Jan 18, 2021

answers: 1

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Answer:

Given,

2x^2+Kx+3

here it is in the form ax^2+bc+C=0

here a=2, b=K, c=3

if it has two equal roots. then ∆=0

b^2-4ac=0

k^2-4(2)(3)=0

k^2-24=0

k^2=24

k=√24

k=+2√6 or -2√6

276

AnaGomez

Jan 18, 2021

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