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Answer. Spiders are able to spin sticky and non-sticky silk. They avoid walking on the sticky silk. In addition, spiders have moveable claws on their feet that grip and release the web's threads as they walk.Liquid metal works exactly like thermal paste: it fills the microscopic gaps on the surface between the CPU/GPU and its heat sink. It's a soft metal with a low melting point and a high boiling point. ... When it's combined with the other components and metals like Indium, the melting point falls to -19C.Answer:

Given :-

A body moving with velocity 40 m/s is brought to rest in 20 seconds.

To Find :-

What is the retardation and the distance travelled by a body.

Formula Used :-

❶To find acceleration we know that,

\boxed{\bold{\large{v\: =\: u\: +\: at}}}

v=u+at

❷ To find distance travelled we know that,

\boxed{\bold{\large{{v}^{2} =\: {u}^{2} +\: 2as}}}

v

2

=u

2

+2as

where,

v = Final velocity

u = Initial velocity

a = Acceleration

t = Time

s = Distance travelled

Solution :-

❶ To find retardation,

Given :

Final velocity = 0 m/s

Initial velocity = 40 m/s

Time = 20 seconds

According to the question by using the formula we get,

⇒ 0 = 40 + a(20)

⇒ 0 - 40 = 20a

⇒ - 40 = 20a

⇒ \dfrac{\cancel{- 40}}{\cancel{20}}

20

−40

= a

⇒ - 2 = a

➠ a = - 2 m/s²

\therefore∴ The retardation of a body is - 2 m/s² .

❷ To find distance travelled,

Given :

Final velocity = 0 m/s

Initial velocity = 40 m/s

Time = 20 seconds

Acceleration = - 2 m/s²

According to the question by using the formula we get,

↦ (0)² = (40)² + 2(- 2) × s

↦ 0 = 1600 - 4 × s

↦ 0 = 1600 - 4s

↦ 0 - 1600 = - 4s

↦ - 1600 = - 4s

↦ \dfrac{\cancel{- 1600}}{\cancel{- 4}}

−4

−1600

= s

↦ 400 = s

➥ s = 400 m

\therefore∴ The distance travelled by a body is 400 m .Answer:

Given :-

A body moving with velocity 40 m/s is brought to rest in 20 seconds.

To Find :-

What is the retardation and the distance travelled by a body.

Formula Used :-

❶To find acceleration we know that,

\boxed{\bold{\large{v\: =\: u\: +\: at}}}

v=u+at

❷ To find distance travelled we know that,

\boxed{\bold{\large{{v}^{2} =\: {u}^{2} +\: 2as}}}

v

2

=u

2

+2as

where,

v = Final velocity

u = Initial velocity

a = Acceleration

t = Time

s = Distance travelled

Solution :-

❶ To find retardation,

Given :

Final velocity = 0 m/s

Initial velocity = 40 m/s

Time = 20 seconds

According to the question by using the formula we get,

⇒ 0 = 40 + a(20)

⇒ 0 - 40 = 20a

⇒ - 40 = 20a

⇒ \dfrac{\cancel{- 40}}{\cancel{20}}

20

−40

= a

⇒ - 2 = a

➠ a = - 2 m/s²

\therefore∴ The retardation of a body is - 2 m/s² .

❷ To find distance travelled,

Given :

Final velocity = 0 m/s

Initial velocity = 40 m/s

Time = 20 seconds

Acceleration = - 2 m/s²

According to the question by using the formula we get,

↦ (0)² = (40)² + 2(- 2) × s

↦ 0 = 1600 - 4 × s

↦ 0 = 1600 - 4s

↦ 0 - 1600 = - 4s

↦ - 1600 = - 4s

↦ \dfrac{\cancel{- 1600}}{\cancel{- 4}}

−4

−1600

= s

↦ 400 = s

➥ s = 400 m

\therefore∴ The distance travelled by a body is 400 m .Answer:

Given :-

A body moving with velocity 40 m/s is brought to rest in 20 seconds.

To Find :-

What is the retardation and the distance travelled by a body.

Formula Used :-

❶To find acceleration we know that,

\boxed{\bold{\large{v\: =\: u\: +\: at}}}

v=u+at

❷ To find distance travelled we know that,

\boxed{\bold{\large{{v}^{2} =\: {u}^{2} +\: 2as}}}

v

2

=u

2

+2as

where,

v = Final velocity

u = Initial velocity

a = Acceleration

t = Time

s = Distance travelled

Solution :-

❶ To find retardation,

Given :

Final velocity = 0 m/s

Initial velocity = 40 m/s

Time = 20 seconds

According to the question by using the formula we get,

⇒ 0 = 40 + a(20)

⇒ 0 - 40 = 20a

⇒ - 40 = 20a

⇒ \dfrac{\cancel{- 40}}{\cancel{20}}

20

−40

= a

⇒ - 2 = a

➠ a = - 2 m/s²

\therefore∴ The retardation of a body is - 2 m/s² .

❷ To find distance travelled,

Given :

Final velocity = 0 m/s

Initial velocity = 40 m/s

Time = 20 seconds

Acceleration = - 2 m/s²

According to the question by using the formula we get,

↦ (0)² = (40)² + 2(- 2) × s

↦ 0 = 1600 - 4 × s

↦ 0 = 1600 - 4s

↦ 0 - 1600 = - 4s

↦ - 1600 = - 4s

↦ \dfrac{\cancel{- 1600}}{\cancel{- 4}}

−4

−1600

= s

↦ 400 = s

➥ s = 400 m

\therefore∴ The distance travelled by a body is 400 m .

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