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answers: 1

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Answer:

Answer:

Toroid

B=

2πr

μ

0

Ni

in free space

B=

2πr

μ

0

μ

r

Ni

in a medium

Given: i=2 A

N=400 turns

circumferential length =2πr=40 cm=0.4 m

B=I T

substituting the values in formula;

I=

0.4

μ

r

μ

0

(400)(2)

. also μ

0

=4π×10

−7

hence μ

r

=

4π×10

−7

×400×2

0.4

=400

hence

μ

r

=400

302

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