contaminate

answers: 1

Register to add an answer

Answer:

HERe IS UR AnS:

In the mentioned figure,

O is the centre of circle,

AB is a chord

AXB is a major arc,

OA=OB= radius = 15 cm

Arc AXB subtends an angle 60° at O.

Area of sector AOB= 60 × π × r^2

360

= 60 × 3.14 × ( 15)^2

360

= 117.75 cm^2

Area of minor segment (Area of Shaded region) = Area of sector AOB− Area of △ AOB

By trigonometry,

AC=15sin30

OC=15cos30

And, AB=2AC

∴ AB=2×15sin30=15 cm

OC = 15 cos 30

= 15 √3

2

= 15 × 1.73

2

= 12.975 cm

∴ Area of △AOB=0.5×15×12.975

=97.3125cm^2

∴ Area of minor segment (Area of Shaded region)=Area of sector AOB− Area of △ AOB

=117.75−97.3125

=20.4375 cm ^2

∴Area of major segment = Area of circle − Area of minor segment

=(3.14×15×15)−20.4375

=686.0625cm ^2

STudY WeLL...
182

Savannah

For answers need to register.

Contacts

mail@expertinstudy.com

Feedback

Expert in study

About us

For new users

For new experts

Terms and Conditions