5 . For the following equilibrium, K =6.3 x 1014 at 1000 K. NO(g)+O3 —–>NO2(g) + O2(g) Both the forward and reverse reactions in the equilibrium are elementary bimolecular reactions. What is Kc for the reverse reaction?DONT SPAM VARNA WARNING NI MILEGI SEEDHA MURDER HOGA

Question

SimonsenL Dec 5, 2020

5 . For the following equilibrium, K =6.3 x 1014 at 1000 K. NO(g)+O3 —–>NO2(g) + O2(g) Both the forward and reverse reactions in the equilibrium are elementary bimolecular reactions. What is Kc for the reverse reaction?DONT SPAM VARNA WARNING NI MILEGI SEEDHA MURDER HOGA

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Answer:

The value of the equilibrium constant for the reverse reaction is obtained from the reciprocal of the value of the equilibrium constant of the forward reaction.

Hence, KC(reverse)=KC1.

Substitute values in the above expression.

KC(reverse)=6.3×10141=1.59×10-¹⁵

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Dogami

Dec 5, 2020

5 . For the following equilibrium, K =6.3 x 1014 at 1000 K. NO(g)+O3 —–>NO2(g) + O2(g) Both the forward and reverse reactions in the equilibrium are elementary bimolecular reactions. What is Kc for the reverse reaction?DONT SPAM VARNA WARNING NI MILEGI SEEDHA MURDER HOGA

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