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15.Calculate the minimum force applied for which themass m stays at rest w.r.t the body of mass Mplzzz answer​

answers: 1
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Answer:

x

10

11

12

13

14

15

f

1

4

7

5

9

8

for a frequency distribution,

So, total number of observation =(1+4+7+5+9+8)=34

It is a even number.

So, median is the value of average of values at (  

2

n

​  

)  

th

 and (  

2

n+2

​  

)  

th

.

∴  Here, median is the average of the values at (  

2

34

​  

)  

th

 or 17  

th

 position and (  

2

34+2

​  

)  

th

 or 18  

th

 position.

x 10  11

12

13

14

15

f

1

4

7

5  9

8

position

1

1+4=5

5+7=12

12+5=17

17+9=26

26+8=34

So, value of x at 17  

th

 position is 13 and at 18  

th

 position is 14.

∴Median=(  

2

13+14

​  

)=  

2

27

​  

=13.5.

Mode for a frequency distribution is the value which is the most common frequent value.

Here 14 has frequency 9 which is highest. So, mode for the frequency distribution is 14.

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Stepan
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