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Force of 1:25 n acts on an object at rest after travelling a distance of 8 metre the speed of object in 10 M/S the mass of the object is as :A) 1.25 kgB) 2.5 kgC )5 kgD) 10kg_____No spam _____Explain well plz

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Answer:

Given Information,

Force Applied (F) = 125 N

Initial Velocity (u) = 0 m/s

Final Velocity (v) = 10 m/s

Displacement (s) = 8m

From Work Energy Theorem,

Net Work Done = Change in Kinetic Energy

Here, initial KE is inconsiquential as the object was at rest initially.

⟶ F × s = 1/2mv²

⟶ 125 × 8 × 2 = 100m

⟶ 100m = 250 × 8

⟶ 100m = 2000

⟶ m = 20Kg

Mass of the object is 20Kg
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