How to find out how muchwill the momentum increase if the kinetic energy of an object is increased by 50%?​

Percentage increase in K.E,

(E)=[

E

1

E

2

−E

1

]×100=[

E

1

E

2

−1]×100

But Eαp

2

⇒

E

1

E

2

=

p

1

2

p

2

2

∴ % increase in K.E. =[

p

1

2

p

2

2

−1]×100

Let p

1

=100, then

p

2

=100+50=150% increase in

K.E.=[

(100)

2

(150)

2

−1]×100=[

100

225

−1]×100

=125%

Therefore, the percentage increase in its kinetic energy is 125%