Kari
Dec 14, 2020

answers: 1

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Answer:

3. 2x^2-7x+6=0

it will have 2 as __root__

substitute 2 in the equation

2x²-7x+6=0

2(2)²-7×2+6=0

2×4-14+6=0

8-8=0

__0=0__

As LHS = RHS

2 is the root of the given equation

332

KatrineLu

Dec 14, 2020

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