Given : Mass of the motorcar, M=1200kg
Initial velocity of the car, u=90 km/h=25 m/s (∵1km/h=185m/s) Final velocity of the car, v=18 km/h=5 m/s Time taken t=4 s ΔP=mv−muΔP=1200×5−1200×25=−24000 kg m/sv=u+at5=25+a×4 ⟹a=−5 m/s2 (-ve shows retardation)∣F∣=m∣a∣=1200×5=6000 N