Pls answer in detail , step by step ......... Don't spam Q . 5 part { B }​

inner circumference =2πr

176=2πr

r=176*7/2*22

r=28m

radius of outer track

R=28+7=35m

area of path=π(R²-r²)

a=22/7*(35²-28²)

a=22/7*441

a=1386m²

b) circumference of outer circle =2πR

=2*22/7*35

=220m

cost=220*12=rupees2640