Maurice Ferguson

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Answer:

*draw**a**ray**OA**.**draw**an**arc**with**help**of**compass**of**any**radii**.**Mark**a**point**on**the**arc**from**point**B**of**radii**equal**to**the**radii**of**arc**.**this**is**the**angle**of**60**degrees**.**Now**construct**the**angle**of**90**degrees**.**(**angle**DOA**=**90**degrees**.**now**bisect**angle**DOC**.*

*hence**;** **angle** **EOA** **=** **75** **degrees**.*

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Saberbrand

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