Marcus Johnson
Jan 30, 2021

answers: 1

Register to add an answer

The time for answering the question is over

Answer:

Answer:|z| = 1

Solution :

Let z = x + iy. Then,

z−1z+1=(x−1)+iy(x+1)+iy×(x+1)−iy(x+1)−iy=(x2+y2−1)+(x+y)i(x+1)2+y2

Now, z−1z+1 is purely imaginary ⇔x2+y2−1=0⇔x2+y2=1⇔|z|=1.

396

Risto

Jan 30, 2021

For answers need to register.

Contacts

mail@expertinstudy.com

Feedback

Expert in study

About us

For new users

For new experts

Terms and Conditions