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Computer Science

reduce the boolean expressions. abef+ ab(ef)'+(ab)'ef.

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ABEF AB(EF)′ (AB)′EF => AB(EF (EF)′) (AB)′EF => AB.I (AB)′EF => AB (AB)′EF => (AB (AB)′)(AB EF) = I.(AB EF) = AB EF

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