Glendale
Feb 8, 2021

answers: 1

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Answer:

Answer

The distance around the track along its inner edge

=EF+HG + circumference of semicircle with diameter EH+circumference of semicircle with diameter FG

circumference of semicircle with diameter EH + Circumference of semicircle with diameter FG

=2×π×30=60πm

∴ The distance around the track along its inner edge

=60π+106+106

=

7

2804

m

∴ Area of track = Area of rectangle ABFE + Area of rectangle HGCD + (Area of semicircle with diameter AD − Area of semicircle with diameter EH) + (Area of semicircle with diameter BC − Area of semicircle with diameter FG)

=(106×10)+(106×10)+(

2

π

×40×40−

2

π

×30×30)+(

2

π

×40×40−

2

π

×30×30)

=2120+2200=4320m

2

421

Morgan

Feb 8, 2021

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