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Answer:

To prove : Area ( ║gm ABCD) = AB × AL. Construction: Draw BM ⊥ DC so that rectangle ABML is formed. Proof: ║gm ABCD and rectangle ABML are on the same base AB and between the same parallel lines AB and LC. ∴ ar( ║gm ABCD) = ar(rectangle ABML) = AB × AL.

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