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Mozius

he electric motor of a model train accelerates the train from rest to 0.720 m/s in 29.0 ms. The total mass of the train is 840 g. Find the average power delivered to the train during its acceleration. W

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326 cents Madison
Answer:

Answer:

7.481W

power= work done÷time

power= force × uniform velocity

a= ∆v/t

29.0ms=

29 \times{10}^{ - 3 } s

=(0.72-0)÷29×10^-3

a=24.83m/s^2

Newton's second law

f=ma

=(0.84×24.83)

=20.86N

w=FD

v^2=u^2+2as

0.5184=0+49.66s

s=0.0104m

20.86×0.0104

=0.216944J

0.216944÷t

P=7.481W

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