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79 nitregon react with 29 hydrogen to form NH3 ,1- which is the limiting reagent? 2, calculate the maximum amount of NH3 that be formed in the reaction?​

answers: 1
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Answer:

The balanced chemical equation is as follows:

N

2

+3H

2

→2NH

3

The molar masses of nitrogen, hydrogen and ammonia are 28 g/mol, 2 g/mol and 17 g/mol respectively.

28 g of nitrogen reacts with 6 g of hydrogen to form 34 g of ammonia.

2.00×10

3

g of nitrogen will react with

28

6

×2.00×10

3

=428.6 g hydrogen.

However, 1.00×10

3

g of dihydrogen are present.

Hence, nitrogen is the limiting reagent.

(i) Mass of ammonia produced =

28

34

×2×10

3

=2428.57 g

(ii) Hydrogen is the excess reagent. Hence, it will remain unreacted.

(iii) Mass of dihydrogen left unreacted =1.00×10

3

−428.6=571.4 g

260
Fumagalli
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