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What mass of sodium hydroxide is formed when 46g of sodium reacts with excess water?please can someone Decideme ASAP

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Answer:

question:-What is the quantity of hydrogen gas liberated when 46 g sodium reacts with excess ethanol ?

[Given At. mass of Na = 23]

ANSWER

2Na+2C

2

H

5

−OH→2C

2

H

5

−ONa+H

2

Moles of 46 g Na =

23g/mol

46g

=2mol

2 moles of Na will give 1 mole of hydrogen.

The molecular weight of hydrogen is 2 g/mol.

Thus the quantity of hydrogen gas liberated is 2.0 g or 2.0×10

−3

kg

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