In figure if angle BCE -95° then find angle BAD​

ANSWER

Let ∠ADB=x

In △ACD,AC=CD

⇒∠CAD=∠CDA=x

and, ∠ACB=∠CAD+∠CDA=x+x=2x

⇒∠BAC=∠ACB=2x.(∵ In ABC,AB=BC)

∴∠BAD=∠BAC+∠CAD

=2x+x=3x

And,

∠ADB

∠BAD

=

x

3x

=

1

3

i.e., ∠BAD:∠ADB=3:1 [henceproved]