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Each of two equal angles of a triangle is twice the third angle. find the angles of the triangle.​

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174 cents Laura Cooper
Answer:

Let the 1st and second angle of triangle=X

the 3nd angle of triangle=2x

X +X+2x =180°

4x=180°

X =180°÷4

=45°

3rd angle 2x

= 2×45

=90°

1st angle =45°

2nd angle= 45°

3rd angle= 90°

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Laura Cooper
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