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Thordiron

what is the deceleration of a vechicle moving in a striate line that changes its velicity from 100km/h to a dead stop 10seconds​

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481 cents Jomand
Answer:

\huge {\underline{\pink{Given:-}}}

  • Initial velocity ,u = 100km/h = 100×5/18 = 500/18 = 27.77 m/s
  • Final velocity ,v = 0m/s
  • Time taken ,t = 10 s

\huge {\underline{\purple{To Find:-}}}

  • Deceleration of vehicle ,a

\huge {\underline{\blue{Solution:-}}}

As we know acceleration is defined as the rate of change in velocity at per unit time.

Negative acceleration is called deceleration .

• a = v-u/t

where,

a is the acceleration/deceleration

v is the final velocity

u is the initial velocity

t is the time taken

Substitute the value we get

→ a = 0-27.77/10

→ a = -27.77/10

→ a = -2.77m/s²

Therefore,the deceleration of the vehicle is 2.77m/.

\huge{\sf{\green{Additional\ Information !!~~ }}}

Some equation of motion are

• v = u +at

• s = ut +1/2at².

• v² = u² + 2as

Here,

v is the final velocity

u is the initial velocity

a is the acceleration

s is the displacement or Distance

t is the time taken

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Jomand
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