Thordiron

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Answer:

- Initial velocity ,u = 100km/h = 100×5/18 = 500/18 = 27.77 m/s

- Final velocity ,v = 0m/s

- Time taken ,t = 10 s

- Deceleration of vehicle ,a

As we know acceleration is defined as the rate of change in velocity at per unit time.

Negative acceleration is called deceleration .

where,

a is the acceleration/deceleration

v is the final velocity

u is the initial velocity

t is the time taken

Substitute the value we get

→ a = 0-27.77/10

→ a = -27.77/10

→ a = -2.77m/s²

Therefore,__the____ ____decele____ration____ of____ the____ ____vehi____cle____ ____is____ ____2____.____7____7____m____/____s²____.__

Some equation of motion are

Here,

v is the final velocity

u is the initial velocity

a is the acceleration

s is the displacement or Distance

t is the time taken

153

Jomand

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