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McIntosh-Mcintosh

A relation between x and y such that the pt. (x,y) is equidistant from the points(7,1) and (3,5)2 pointsx+y = 2x-y + 2x+y = 3​

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Answer:

Correct question :-

A relation between x and y such that the pt. (x,y) is equidistant from the points (7,1) and (3,5) :-

a) x+y = 2

b) x-y = 2

c) x+y = 3

Solution :-

If point (x ,y) is equidistant from the points (7,1) and (3,5). So (x,y) is midpoint of line joining (7,1) and (3,5).

Co-ordinates of midpoint of line joining (7,1) and (3,5) can be written as :-

 \rm\implies\bigg( \dfrac{7 + 3}{2} \:, \: \dfrac{1 + 5}{2}\bigg)

\rm\implies\bigg( \dfrac{10}{2} \:, \: \dfrac{6}{2}\bigg)

\rm\implies\bigg( 5 \:, \:3\bigg)

 \therefore\rm(x,y) = (5,3)

=> x = 5

=> y = 3

Now , x - y = 5-3 = 2

Therefore option (b) is correct.

Answer :

  • b) x-y = 2

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Learn more :

Co-ordinates of midpoint of line joining (a,b) and (c,d) is given as :-

 \rm\implies\bigg( \dfrac{a + c}{2} \:, \: \dfrac{b + d}{2} \bigg)

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Christopher
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