answers: 1

Register to add an answer

The time for answering the question is over

Answer:

ProvidEd that:

- Initial velocity = 0 m/s
- Acceleration = 0.1 m/s sq.
- Time = 2 minutes

To calculaTe:

- Speed acquired
- Distance travelled

SoluTion:

- Speed acquired = 12 m/s
- Distance travelled = 720 m

KnowlEdge required:

- SI unit of speed = m/s
- SI unit of time = seconds
- SI unit of distance = m
- SI unit of acceleration = m/s²

UsiNg concepts:

• Formula to convert min-sec.

• First equation of motion to calculate the speed acquired.

• Third equation of motion / Second equation of motion to calculate distance.

Using formulas:

• 1 min = 60 seconds

• 1st eqⁿ of motion → v = u + at

→ 2nd eqⁿ of motion → s = ut + ½ at²

→ 3rd eqⁿ of motion → v² - u² = 2as

Required solution:

~ Firstly let us convert min-sec!

⇝ 1 min = 60 seconds

⇝ 2 minutes = 2 · 60

⇝ 2 minutes = 120 seconds

- Henceforth, converted!

~ Now by using first equation of motion let us find out the speed acquired!

⇝ v = u + at

⇝ v = 0 + 0.1(120)

⇝ v = 0 + 12

⇝ v = 12 m/s

⇝ Final velocity = 12 m/s

- Speed acquired = 12 m/s

~ Now finding distance travelled!

By using second equation of motion...

⇝ s = ut + ½ at²

⇝ s = 0(120) + ½ · 0.1(120)²

⇝ s = 0 + ½ · 0.1 · 14400

⇝ s = 0 + ½ · 1440

⇝ s = 0 + 720

⇝ s = 720 metres

⇝ Distance = 720 metres

- Distance travelled = 720 m

By using third equation of motion...

⇝ v² - u² = 2as

⇝ (12)² - (0)² = 2(0.1)(s)

⇝ 144 - 0 = 0.2s

⇝ 144 = 0.2s

⇝ 144/0.2 = s

⇝ 1440/2 = s

⇝ 720 = s

⇝ s = 720 metres

⇝ Distance = 720 metres

- Distance travelled = 720 m

AdditioNal information:

Difference between speed and velocity is mentioned below:

_______________________

Hello dear users, with due respect I want to say that we can find out the distance by using either third equation of motion or second equation of motion, choice may vary! I solve this part by both methods for you, you can use any one of them! Thank you!

242

Beth Garcia

For answers need to register.

Contacts

mail@expertinstudy.com

Feedback

Expert in study

About us

For new users

For new experts

Terms and Conditions