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Mightcrusher

shathaka sudha padhyam 6th padhyam bhavam plz answer me don't tell sorry I don't this language don't answer that plz​

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Answer:

Answer:

The point on y axis which is equidistant from (- 5, 2) and (-9 -2) is (0,-7).

To find : The point on y axis which is equidistant from (- 5, 2) and (-9 -2) ?

Solution :

Let the point on y axis be (0,y) as x coordinate is 0 on y-axis.

So, the point (0,y) is equidistant from (- 5, 2) and (-9 -2).

i.e. their distance is equal.

Applying distance formula, d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}d=

(x

2

−x

1

)

2

+(y

2

−y

1

)

2

\sqrt{(0-(-5))^2+(y-2)^2}=\sqrt{(-9-0)^2+(-2-y)^2}

(0−(−5))

2

+(y−2)

2

=

(−9−0)

2

+(−2−y)

2

25+y^2+4-4y=81+4+y^2+4y25+y

2

+4−4y=81+4+y

2

+4y

29-4y=85+4y29−4y=85+4y

8y=-568y=−56

y=\frac{-56}{8}y=

8

−56

y=-7y=−7

Therefore, the point on y axis which is equidistant from (- 5, 2) and (-9 -2) is (0,-7).

#Learn more

Find the point of the y axis which is equidistant from the points (6,2) and (2,10)

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