Find the equation of a straight line which passes through thepoint of intersection of 3x + 4y - 1 = 0 and 2x - 5y + 7 = 0 andwhich is perpendicular to 4x - 2y + 7 = 0.​

• 3x + 4y - 1 = 0⠀⠀----[1]
• 2x - 5y + 7 = 0 ⠀ ----[2]
• 4x - 2y + 7 = 0⠀⠀----[3]

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• Equation of line AB.

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• Let two points, and .

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It is given that two lines i.e., 3x + 4y - 1 = 0 and 2x - 5y + 7 = 0 are intersecting each other.

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⠀⠀❍ Let us find the intersecting point.

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• x = -1
• y = 1

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.

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Now, let's find the slope of the third line.

Writing it in the form of

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Therefore,

• Slope of the line is 2.

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We know that, product of slope of two lines that are perpendicular to each other is -1.

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• The required equation of the line is .