The sum of two integers is greater than 12. One integer is 10 less than the other. What are the values of the integers?

Let's set up an equation:

x plus y is greater than 12

x + y > 12

One of the integers is ten less than twice the other one

x = 2y -10

Time to start solving:

(2y-10) + y > 12
2y + y > 12 + 10
3y > 22 
3y=24
y=8

Now its time to find the value of x:

x=2(8) - 10
x=16-10
x= 6

6 + 8 > 12, 6+8 is greater than twelve.

In conclusion we can wrap up that 6 and 8 are the least value integers.