broom

answers: 1

Register to add an answer

The time for answering the question is over

340 cents

Answer:

Let's set up an equation:

x plus y is greater than 12

x + y > 12

One of the integers is ten less than twice the other one

x = 2y -10

Time to start solving:

(2y-10) + y > 12

2y + y > 12 + 10

3y > 22

3y=24

y=8

Now its time to find the value of x:

x=2(8) - 10

x=16-10

x= 6

6 + 8 > 12, 6+8 is greater than twelve.

In conclusion we can wrap up that 6 and 8 are the least value integers.

x plus y is greater than 12

x + y > 12

One of the integers is ten less than twice the other one

x = 2y -10

Time to start solving:

(2y-10) + y > 12

2y + y > 12 + 10

3y > 22

3y=24

y=8

Now its time to find the value of x:

x=2(8) - 10

x=16-10

x= 6

6 + 8 > 12, 6+8 is greater than twelve.

In conclusion we can wrap up that 6 and 8 are the least value integers.

351

Dmitrij

For answers need to register.

Contacts

mail@expertinstudy.com

Feedback

Expert in study

About us

For new users

For new experts

Terms and Conditions