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Si mezclan 400 g de agua a 40 °C con 600g de agua a 80°C ¿cuál es la temperatura final de la mezcla? considerando el calor específico del agua 1 cal/g°C​

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352 cents Gavinranara
Answer:

60°C

400g (1 cal/g°C) (tf -40°C) = 600g (1 cal/g°C) (80°C -tf)

(tf -40°C) = (80°C -tf)

2tf = 80+40

tf = 120/2

tf= 60°C

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