Elena

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Answer:

A train is running at a speed 32 Km/h and the driver applies the break for 10 second

then the train reaches to the speed of 12 Km/h. find the(retardation) acceleration and

distance covered by the train?

initial velocity =72 km/h=20m/s

final velocity=36km/h=

time equal to 30 seconds

acceleration =∆v/t

(10-20)/30

-10/30

-1/3ms^-2

retardation=1/3ms^-2

distance equal to speed by time

20/30m

2/3m

32

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