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The sum of numerator and denominator of a fraction is greater by 1 than thrice the numerator is decreased by 1 then the fraction reduced to 1/3 find the fraction​

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91 cents Majsaka
Answer:
S O L U T I O N :

Let the place of numerator be x & let the place of denominator be y respectively.

  • The fraction become = x/y

According to the question :

1st case :

➝ x + y = 3x + 1

➝ x - 3x = 1 - y

➝ -2x = 1 - y............(1)

2nd case :

➝ x - 1/y = 1/3

➝ 3(x - 1) = y(1)

➝ 3x - 3 = y............(2)

∴Putting the value of y in equation (1), we get;

➝ -2x = 1 - (3x - 3)

➝ -2x = 1 - 3x + 3

➝ -2x = -3x + 4

➝ -2x + 3x = 4

➝ x = 4

∴ Putting the value of x in equation (1), we get;

➝ -2(4) = 1 - y

➝ -8 = 1 - y

➝ -8 - 1 = -y

➝ -9 = -y

➝ y = 9

Thus,

  • Numerator, (N) = 4
  • Denominator, (D) = 9

The fraction will be x/y = 4/9 .

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Majsaka
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