slipper
Feb 8, 2021

answers: 1

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Answer:

The ordinates of point of intersection of the line 4y=3x+8 and parabola y

2

=8x are wrt of equation

y

2

=8(

3

4y−8

) [On eliminating x between 4y=3x+8 and y

2

=8x]

⇒3y

2

−32y+64=0

⇒(3y−8)(y−8)=0

y=

3

8

or y=8

Putting y=

3

8

and y=8 in 4y=3x+8 successively we get x=

9

8

and x=8

The line 4y=3x+8 and parabola y

2

=8x at P(

9

8

,

3

8

) and Q(8,8) length of chord PQ=

(8−

9

8

)

2

+(8−

3

8

)

2

=

9

80

.

464

Goransson

Feb 8, 2021

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