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LaQuestion 21. A rod of cross sectional area A is floating as shown in figure below. The density ofliquid A is P., that of liquid B is p, and that of the body is Po. Find the buoyant force on the rod duev liquid A and liquid B.​

answers: 1
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Answer:

At equilibrium the weight of the body and buoyant force balance each other.

When body is displace down by x, then the upward force is due to increase in buoyant force due to more displacement of liquid.

F=−Vρg=−ρAxg −ve sign is because displacement and force are in opposite direction

Acceleration=a=

M

−rhoAxg

=

ρ

o

AL

−ρAg

x=−ω

2

x

ω=

ρ

o

L

ρg

Time period =T=

ω

=2π

ρg

ρ

o

L

Answer-(B)

solution

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