Find the equation of circle having (2,-7) and (8,1) as ends of a diameter.

Using diameter form,the equation of the circle having A(−2,−3) and B(−3,−5) as the end points of a diameter is

(x−(−2))(x−(3))+(y−(−3))(y−(−5))=0

⇒(x+2)(x+3)+(y+3)(y+5)=0

⇒x2+2x+3x+6+y2+3y+5y+15=0

⇒x2+y2+5x+8y+21=0 is the required equation of the circle.

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