Faubert Julien

answers: 1

Register to add an answer

Answer:

hope it helps you :)

Consider two triangle ΔEGH and ΔEFG

Side EG is common side of both the triangle.

EF = FG = GH = HE

therefore all the sides are equal.

By SSS rules, these 2 triangles are congruent.

To prove EG bisects Angela E and Angele G both

Corresponding parts of congruent triangles are congruent.

Therefore <HEG = <GEF and <EGH = <EGF

so, EG bisects Angela E and Angele G both

324

rubbish

For answers need to register.

199

cents

The time for answering the question is over

Contacts

mail@expertinstudy.com

Feedback

Expert in study

About us

For new users

For new experts

Terms and Conditions