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Faubert Julien

EFGH is a rhombus. Show that EG bisects angle E and angle G both.plz tell fast in hand written format becoz it is more easy to undertand that format​

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Answer:

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Consider two triangle ΔEGH and ΔEFG

Side EG is common side of both the triangle.

EF = FG = GH = HE

therefore all the sides are equal.

By SSS rules, these 2 triangles are congruent.

To prove EG bisects Angela E and Angele G both

Corresponding parts of congruent triangles are congruent.

Therefore <HEG = <GEF and <EGH = <EGF

so, EG bisects Angela E and Angele G both

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