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(a) Construct a AABC in which AB 4 cm, BC 6 cmand AC 7 cm. Construct its similar ABCwhose side AB = 5 cmGE​

answers: 1
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Answer:

Steps:

1. draw base AB=4cm

2. with A as center, with a scale of 5cm as radius draw an arc and with B as center, with a scale of 6cm as radius draw an arc.

3. let C be the point of intersection of the above 2 lines.

4. draw a ray AX making an acute angle with line AB on the opposite side if the vertex C.

5. mark 3 points A1,A2,A3 such tha A1A2=A2A3=A3A1

6. join A3B and draw a parallel line B

A2

7. draw a line parallel to BC to intersect AC at C

Thus AB

C

is a required triangle.

Justification;

By construction,

AB ' / AB= AA3/AA2 = 32

also B ′ C ′ ∥ BC

∴∠AB ′ C ′ =∠ABC

In △AB ′ C ′ ,△ABC

∠A=∠A,∠AB ′ C ′=∠ABC

△AB

C

∼△ABC

AB

AB

=

AC

AC

=

BC

B

C

AB

AB

=

AC

AC

=

BC

B

C

=

3

2

solution

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Felak
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