James Lawrence

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Answer:

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S(m):S(n)=m²:n²

then let S(m) and S(n) be m²x and n²x respectively

then S(m-1) and S(n-1) will be (m-1)²x and (n-1)²x respectively

the T(m) will be S(m)-S(m-1) or m²x-(m-1)²x or (2m-1)x

similarly T(n) will be (2n-1)x

hence T(m):T(n) is (2m-1):(2n-1).

(proved)

300

Yana

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