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\sf\large\underline\purple{Given:-}

Given:−

\sf{\implies Principal=Rs.25000}⟹Principal=Rs.25000

\sf{\implies Time=3\: years}⟹Time=3years

\sf{\implies Rate=12\%}⟹Rate=12%

\sf\large\underline\purple{To\:Find:-}

ToFind:−

\sf{\implies Amount\:_{(at\:the\:end\:of\:3\: years)}=?}⟹Amount

(attheendof3years)

=?

\sf\large\underline\purple{Solution:-}

Solution:−

To calculate amount at the end of 3 years ,at first we have to apply a formula of compound interest. By substituting the above value we get the amount at the end of 3 years.

\tt{\implies A=P\bigg(1+\dfrac{r}{100}\bigg)^n}⟹A=P(1+

100

r

)

n

\tt{\implies A=25000\bigg(1+\dfrac{12}{100}\bigg)^3}⟹A=25000(1+

100

12

)

3

\tt{\implies A=25000\bigg(\dfrac{100+12}{100}\bigg)^3}⟹A=25000(

100

100+12

)

3

\tt{\implies A=25000\bigg(\dfrac{112}{100}\bigg)^3}⟹A=25000(

100

112

)

3

\tt{\implies A=25000*(1.12)^3}⟹A=25000∗(1.12)

3

\tt{\implies A=25000*1.404928}⟹A=25000∗1.404928

\tt{\implies A=35123.2}⟹A=35123.2

\sf\large{Hence,}Hence,

\sf{\implies Amount\:_{(at\:the\:end\:of\:3\: years)}=Rs < /p > < p > .35123.2}⟹Amount

(attheendof3years)

=Rs</p><p>.35123.2