 # Ila jp nan busy ila suma irukan.. ​

The time for answering the question is over
334 cents \sf\large\underline\purple{Given:-}

Given:−

\sf{\implies Principal=Rs.25000}⟹Principal=Rs.25000

\sf{\implies Time=3\: years}⟹Time=3years

\sf{\implies Rate=12\%}⟹Rate=12%

\sf\large\underline\purple{To\:Find:-}

ToFind:−

\sf{\implies Amount\:_{(at\:the\:end\:of\:3\: years)}=?}⟹Amount

(attheendof3years)

=?

\sf\large\underline\purple{Solution:-}

Solution:−

To calculate amount at the end of 3 years ,at first we have to apply a formula of compound interest. By substituting the above value we get the amount at the end of 3 years.

\tt{\implies A=P\bigg(1+\dfrac{r}{100}\bigg)^n}⟹A=P(1+

100

r

)

n

\tt{\implies A=25000\bigg(1+\dfrac{12}{100}\bigg)^3}⟹A=25000(1+

100

12

)

3

\tt{\implies A=25000\bigg(\dfrac{100+12}{100}\bigg)^3}⟹A=25000(

100

100+12

)

3

\tt{\implies A=25000\bigg(\dfrac{112}{100}\bigg)^3}⟹A=25000(

100

112

)

3

\tt{\implies A=25000*(1.12)^3}⟹A=25000∗(1.12)

3

\tt{\implies A=25000*1.404928}⟹A=25000∗1.404928

\tt{\implies A=35123.2}⟹A=35123.2

\sf\large{Hence,}Hence,

\sf{\implies Amount\:_{(at\:the\:end\:of\:3\: years)}=Rs < /p > < p > .35123.2}⟹Amount

(attheendof3years)

=Rs</p><p>.35123.2

To solve the word problems of compound interest at first we have to know something concept about compound interest as you know that in the question of compound interest time is given yearly , half yearly , quarterly so, if time is given half yearly or quarterly then we have to change the time as well as it's rate. To change the time of compound interest , we have to multiply by 2 and in rate dividing by 2 if the time is given in half yearly. If time is given in quarterly then we have to multiply by 3 and in rate dividing by 3. In annually time is not changed. We have to something about principal. It may be lending or borrowing , sum of money, loan ect in the question. Rate means The extra amount you have to pay as per the interest.

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