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Find the relative molecular mass of (i) CaCO3 and (ii) HNO3 (iii)HCl(Given Ca = 40 u ; Cl = 35.5 u ; H = 1 u ; N = 14 u ; O = 16 u)

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75 cents Annette Alvarado
Answer:

(i) CaCO3: 100 g/mol

(ii)HNO3:63g/mol

(iii)HCl: 36.5g/mol

CaCO3= molecular mass of Ca+ molecular mass of C+3×molecular mass of O

=40+12+3×16=100

HNO3=molecular mass of H+ molecular mass of N+ 3×molecular mass of O

=1+14+3×16=63

HCl=molecular mass of H + molecular mass of Cl

=1+35.5=36.5

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Annette Alvarado
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