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67.29 was rounded to 2 decimal places.What is the upper bound?

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                   JUST DEW IT CORPORATION

                                 Balance Sheet

                                For 2017 and 2018

                                             2017        2018        Cash

                                                                             source / use

Assets:

Current assets

Cash                                    $12,157     $14,105    source

Accounts receivable        $29,382     $32,815    use

Inventory                           $54,632    $57,204     use

Total current assets           $96,171    $104,124

Non-current assets

Net plant and equip.       $367,241   $375,830    use

Total assets                     $463,412   $479,954

Liabilities and stockholders' equity:

Current liabilities

Accounts payable            $46,382     $49,276      source

Notes payable                  $18,246       $19,784     source

Total current liabilities     $64,628     $69,060

Long term debt

Long-term debt                $49,000     $45,000     use

Owners’ equity

Common stock and

paid-in surplus                 $50,000      $50,000        -

Retained earnings          $299,784     $315,894     source

Total owners' equity       $349,784    $365,894

Total liabilities and

stockholders' equity:       $463,412    $479,954

Market- value Balance sheet

ASSETS

NON-CURRENT ASSETS                                                 $37,628

CURRENT ASSETS                                                           $11,274

TOTAL ASSETS                                                                $48,908

EQUITY AND LIABILITIES          

EQUITY (316.6*$103.39)=32,733.274                             $32,733

LIABILITIES

NON-CURRENT                                                                $10,419

CURRENT LIABILITIES                                                     $5,750

TOTAL EQUITY AND LIABILITIES                                   $48,908

b) Assets are extra by ($37,628.274 - $22,293) =$15335.27

Hello!

To study if the average dollars spend per shopper is different than the expected population average of $84.5 there was a sample of 120 shoppers taken and their spending habit registered.

Then the study variable is:

X: Amount of money spent by a shopper ($)

This population standard deviation is σ= $16

Using the data information I've run a normality test, with p-value: 0.3056 against the test significance level α: 0.05, the decision is to not reject the null hypothesis so there is enough statistical evidence to conclude that the study variable has a normal distribution.

X~N(μ;σ²)

I've also calculated the sample mean and standard deviation:

X[bar]= $81.01

S= $19.62

a.

If the objective is to test that the true mean spending for the population is significantly different than the expected average of 84.5, the parameter of interest is the population mean μ and the hypothesis test will be two-tailed.

H₀: μ = 84.5

H₁: μ ≠ 84.5

α:0.05

The statistic is a standard normal for one sample:

p-value two tailed  0.016894

b.

The decision rule using the p-value method is:

If p-value ≤ α ⇒ Reject the null hypothesis.

If p-value > α ⇒ Do not reject the null hypothesis.

Since the p-value is less than the significance level, the decision is to reject the null hypothesis.

c.

Using a level of significance of 5% the null hypothesis was rejected. So there is enough statistical evidence to support the researcher's claim that the true mean spending for the population is significantly different than the expected average of $84.5.

I hope it helps!

I am darn sin totally positive the answer is big fat B. For lovely bravoI'm not good at mathJust show us a pictureThe answer is definitely B I agree with catnaster
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