Bengt

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Answer:

7)a)10ab-5cb-10ad+5cd

=10ab-10ad-5cb+5cd

=10a(b-d)-5c(b-d)

=(b-d)(10a-5c)

b)ab²-bc²-ab+c²

=ab²-ab-bc²+c²

=ab(b-1)-c²(b-1)

=(b-1)(ab-c²)

c)3ac+2bc+3ad+2bd

=3ac+3ad+2bc+2bd

=3a(c+d)+2b(c+d)

=(c+d)(3a+2b)

d)axy²+3x+2a²y²+6a

=axy²+3x+2a²y²+6a

=x(ay²+3)+2a(ay²+3)

=(ay²+3)(x+2a)

e)7ab+9cd+7ad+9bc

=7ab+7ad+9cd+9bc

=7a(b+d)+9c(b+d)

=(b+d)(7a+9c)

f)x^4+6x²y+3x³+18xy

=x^4+3x³+6x²y+18xy

=x³(x+3)+6xy(x+3)

=(x+3)(x³+6xy)

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