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Physics
Lena Davis

1. The area of a rectangle is 35 sq m. If the length be 7 cm, then the perimeter of the rectangle is??​

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Answer:

\begin{gathered}\dag\;{\underline{\frak{Given:-}}}\\ \\\end{gathered}

Need to find: Perimeter of the Rectangle?

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☯ Let Breadth of Rectangle be x cm.

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\begin{gathered}\dag\;{\underline{\frak{We\;know\;that,}}}\\ \\\end{gathered}

\begin{gathered}\star\;{\boxed{\sf{\purple{Area_{\;(rectangle)} = Length \times Breadth}}}}\\ \\\end{gathered} ⋆

\begin{gathered}:\implies\sf 0.07 \times x = 35\\ \\\end{gathered}

\begin{gathered}:\implies\sf x = \cancel{ \dfrac{35}{0.07}}\\ \\\end{gathered}

\begin{gathered}:\implies{\boxed{\sf{\pink{x = 500\;m}}}}\;\bigstar\\ \\\end{gathered}

\therefore\;{\underline{\sf{Thus,\;Breadth\;of\;rectangle\;is\; \bf{500\;m}.}}}

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Now, Finding area of rectangle,

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\begin{gathered}\star\;{\boxed{\sf{\purple{Perimeter_{\;(rectangle)} = 2(Length + Breadth)}}}}\\ \\\end{gathered}

Now, We have,

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Length of Rectangle, l = 0.07 m

Breadth of Rectangle, b = 500 m

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\begin{gathered}:\implies\sf Perimeter_{\;(rectangle)} = 2(0.07 + 500)\\ \\\end{gathered}

\begin{gathered}:\implies\sf Perimeter_{\;(rectangle)} = 2 \times 500.07\\ \\\end{gathered}

\begin{gathered}:\implies{\boxed{\sf{\pink{Perimeter= 1000.14\;m}}}}\;\bigstar\\ \\\end{gathered}

\therefore\;{\underline{\sf{Hence,\;The\; Perimeter\;of\;rectangle\;is\; \bf{1000.14\;m}.}}}

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