Shann

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Answer:

Answer: 256/7 cm^2

area of designed region

= area of 1st quadrant + area of 2nd quardant

- area of square .

Area of 1st quardant= Thita÷360×πr^2

Area of 1st quardant= Thita÷360×πr^2 =90÷360×22÷7×8^2

= 1÷4×22÷7×8×8

= 22÷7×2×8

= 352÷7cm^2

For 2nd quardant,

As radius and angle are same

Area of 2nd quardant = area of 1st quardant

=352÷7 cm^2

Now,

Area of square= side× side

= 8 × 8

= 64

Area of designed region= area of 1st quardant +

area of 2nd quardant -

area of square.

= { 352÷7 + 352÷7 + 64}

= { 352 + 352+ 64×7 ÷ 7}

= { 700 - 448 ÷ 7}

= 256÷7 cm^2 ( Answer)

Hope it helps you.

Thank you.

☺️

441

David Armstrong

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