Physics # a object is placed 0.28m from a concave mirror whose focal length 0.1m find the where the image is formed? is the image real (or) vertual​

Image distance, v = -0.155 m

Height of the image, hi = -0.222 m

Given:

Object distance, u = -0.28 m = -28 cm

Object distance, u = -0.28 m = -28 cmFocal length, f = -0.1 m = -10 cm

Object distance, u = -0.28 m = -28 cmFocal length, f = -0.1 m = -10 cmHeight of object, ho = 0.04 m = 4 cm

Object distance, u = -0.28 m = -28 cmFocal length, f = -0.1 m = -10 cmHeight of object, ho = 0.04 m = 4 cmTo find:

Object distance, u = -0.28 m = -28 cmFocal length, f = -0.1 m = -10 cmHeight of object, ho = 0.04 m = 4 cmTo find:Image distance, v = ?

Object distance, u = -0.28 m = -28 cmFocal length, f = -0.1 m = -10 cmHeight of object, ho = 0.04 m = 4 cmTo find:Image distance, v = ?Height of Image, hi = ?

Object distance, u = -0.28 m = -28 cmFocal length, f = -0.1 m = -10 cmHeight of object, ho = 0.04 m = 4 cmTo find:Image distance, v = ?Height of Image, hi = ?Other Variables Required:

Object distance, u = -0.28 m = -28 cmFocal length, f = -0.1 m = -10 cmHeight of object, ho = 0.04 m = 4 cmTo find:Image distance, v = ?Height of Image, hi = ?Other Variables Required:Magnification, m = ?

Object distance, u = -0.28 m = -28 cmFocal length, f = -0.1 m = -10 cmHeight of object, ho = 0.04 m = 4 cmTo find:Image distance, v = ?Height of Image, hi = ?Other Variables Required:Magnification, m = ?Formulas Used:

Object distance, u = -0.28 m = -28 cmFocal length, f = -0.1 m = -10 cmHeight of object, ho = 0.04 m = 4 cmTo find:Image distance, v = ?Height of Image, hi = ?Other Variables Required:Magnification, m = ?Formulas Used:Mirror formula, 1/f = 1/v + 1/u

Object distance, u = -0.28 m = -28 cmFocal length, f = -0.1 m = -10 cmHeight of object, ho = 0.04 m = 4 cmTo find:Image distance, v = ?Height of Image, hi = ?Other Variables Required:Magnification, m = ?Formulas Used:Mirror formula, 1/f = 1/v + 1/uMagnification, m = -v/u = hi/ho

75 