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The given system of equation is

x/(y/2) =4...(i)

(x/3)+2y =5...(ii)

From (1) we get

(2x+y)/2 =4

2x+y=8

y=8-2x

From (2) we get,

x+6y=15..(iii)

Substituting y=8-2x in (iii), we get

x+6(8-2x)=15

x+48-12x=15

=> - 11x =15-48

=> - 11x= -33

=> x= (- 33/-11) =3

Putting x= 3 in y=8-2x we get,

y= 8-2*3

y=8-6

y=2

Hence the solution of the given system is x=3, y=2